In a right-angled triangle ABC, where angle ABC is 90 degrees, let BH be the altitude from B to AC and BD be the bisector of angle ABC. The bisector of angle AHB intersects AB at E, and the bisector of angle BHC intersects BC at F. If M is the midpoint of BD, prove that the points E, M, and F are collinear.

Right triangle stands tall,
Bisectors meet, paths align,
E, M, F in line.
| Key | Description |
|---|---|
| Right-Angled Triangle ABC | A triangle with one angle measuring 90 degrees, with vertices labeled as A, B, and C. |
| Angle ABC | The right angle (90 degrees) in the triangle, located at vertex B. |
| Altitude BH | A perpendicular line segment from vertex B to the hypotenuse AC. |
| Bisector BD | A line segment from vertex B that bisects angle ABC, meeting AC at point D. |
| Point E | The point where the bisector of angle AHB intersects side AB. |
| Point F | The point where the bisector of angle BHC intersects side BC. |
| Midpoint M | The point that is exactly halfway along BD. |
| Collinear Points E, M, F | The points E, M, and F lie on a single straight line. |
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Collinear Points
Angle
of 45 degrees
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