In a right-angled triangle ABC, where angle ABC is 90 degrees, let BH be the altitude from B to AC and BD be the bisector of angle ABC. The bisector of angle AHB intersects AB at E, and the bisector of angle BHC intersects BC at F. If M is the midpoint of BD, prove that the points E, M, and F are collinear.
Right triangle stands tall,
Bisectors meet, paths align,
E, M, F in line.
Key | Description |
---|---|
Right-Angled Triangle ABC | A triangle with one angle measuring 90 degrees, with vertices labeled as A, B, and C. |
Angle ABC | The right angle (90 degrees) in the triangle, located at vertex B. |
Altitude BH | A perpendicular line segment from vertex B to the hypotenuse AC. |
Bisector BD | A line segment from vertex B that bisects angle ABC, meeting AC at point D. |
Point E | The point where the bisector of angle AHB intersects side AB. |
Point F | The point where the bisector of angle BHC intersects side BC. |
Midpoint M | The point that is exactly halfway along BD. |
Collinear Points E, M, F | The points E, M, and F lie on a single straight line. |
Geometry Problems
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Angles
Triangle
Right Triangle
Angle Bisector
Perpendicular lines
Midpoint
Altitude
Collinear Points
Angle
of 45 degrees
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