Dynamic Geometry Problem 1463: Parallelogram, Interior Point, Opposite Triangles with Equal Sum of Areas.
Let ABCD be a parallelogram with a point P inside ABCD (see the figure below). If S1 = Area APB, S3 = Area CPD, S2 = Area BPC, and S4 = Area APD, prove that S1 + S3 = S2 + S4.
Static Diagram of Geometry Problem 1463
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