The figure below shows two squares ABCD and EFGH so that A, D, E,
and H are collinear points. Line AF cuts BE at J and BH at K, Line DF cuts
BE at L and BH at M. If area AJLD = S_{1}, area BKJ = S_{2},
area KFM = S_{3}, and
area LMHE = S_{4}, prove that S_{1} + S_{3} = S_{2} + S_{4}.

A conformal mapping or conformal transformation is a continuous mapping preserving the form of infinitesimal figures. This conformal map produces a realistic view of the original image or map. This the conformal transformation of problem1426

See also: Typography and poster of problem 1417.

Geometry Problems

Ten problems: 1411-1420

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