The figure below shows two squares ABCD and EFGH so that A, D, E,
and H are collinear points. Line AF cuts BE at J and BH at K, Line DF cuts
BE at L and BH at M. If area AJLD = S1, area BKJ = S2,
area KFM = S3, and
area LMHE = S4, prove that S1 + S3 = S2 + S4.
A conformal mapping or conformal transformation is a continuous mapping preserving the form of infinitesimal figures. This conformal map produces a realistic view of the original image or map. This the conformal transformation of problem1426
See also: Typography and poster of problem 1417.