The figure below shows two squares ABCD and EFGH so that A, D, E, 
	  and H are collinear points. Line AF cuts BE at J and BH at K, Line DF cuts 
	  BE at L and BH at M. If area AJLD = S1, area BKJ = S2, 
	  area KFM = S3, and 
	  area LMHE = S4, prove that S1 + S3 = S2 + S4.
 



A conformal mapping or conformal transformation is a continuous mapping preserving the form of infinitesimal figures. This conformal map produces a realistic view of the original image or map. This the conformal transformation of problem1426
See also: Typography and poster of problem 1417.
Geometry Problems
		
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