Geometry Problems, Online Education

Problem 1329: Two Squares Side by Side, Parallel, Perpendicular, 90 Degrees, Congruence.

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The figure below shows the squares ABCD and DEFG (E on CD). GE extended meets BC at H. CM is parallel to HG (M on FG). Prove that (1) AH = HM; (2) angle AHM = 90 degrees.
 

Geometry Problem 1329: Two Squares Side by Side, Parallel, Perpendicular, 90 Degrees, Congruence.

See also:
Art of problem 1312
 

Home | Geometry | Problems | All Problems | Open Problems | Visual Index | Ten problems: 1321-1330 | Triangle | Square | Parallel lines | Perpendicular line | Angle | Congruence | View or Post a solution | by Antonio Gutierrez