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The figure below shows the squares ABCD and DEFG (E on CD). GE extended meets BC at H. HK is perpendicular to AE (K on DG). Prove that AH and HK are congruent.

See also: Sketch of problem 1328

Home | Geometry | Problems | All Problems | Open Problems | Visual Index | Ten problems: 1321-1330 | Triangle | Square | Perpendicular line | Angle | Congruence | View or Post a solution | by Antonio Gutierrez