In a triangle ABC, X is a point on BC and AY is the bisector of the angle 
	  CAX as shown in the figure. The circumcircle of the triangle ABX cuts AY 
	  at Z. BZ extended meets AC at W. Prove that angle XBZ + angle WXZ = angle 
	  XWY. This entry contributed by Sumith Peiris, Moratuwa, Sri Lanka.
 
 
						
               		  
 
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Geometry Problems
		Ten problems: 1321-1330
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	Sketch of problem 1322
Geometry Problems
Ten problems: 1321-1330
						
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