In a triangle ABC, X is a point on BC and AY is the bisector of the angle
CAX as shown in the figure. The circumcircle of the triangle ABX cuts AY
at Z. BZ extended meets AC at W. Prove that angle XBZ + angle WXZ = angle
XWY. This entry contributed by Sumith Peiris, Moratuwa, Sri Lanka.
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Geometry Problems
Ten problems: 1321-1330
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Triangle
Angle Bisector
Circle
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Sketch of problem 1322
Geometry Problems
Ten problems: 1321-1330
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