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              The figure below shows an arbelos ABC (AB, BC, and AC are semicircles of centers O1, O2, 
				and O) and the squares ABB1B2 and BCC1C2. 
				If M1 and M2 are the midpoints of B1B2 
				and C1C2, respectively, prove that AM2 
				and CM1 intersect at I, the incenter of the arbelos.
 
 
                
               
 See also:
 Typography of problem 1301
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