| 
                
		                
		The figure shows a triangle ABC with the 
		altitudes AA1, BB1, and CC1. If B1D 
		is perpendicular to AB, and B1E is perpendicular to BC, prove that 
		DE is equal to the semiperimeter of the triangle A1B1C1.Note: The triangle A1B1C1  
		is called the orthic triangle of the triangle ABC.
 
				  
 
				  |