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              In the figure below, given a triangle 
				ABC, S1 is the area of contact triangle of the 
				incircle, Sa, Sb, and Sc are 
				the areas of the contact triangles of the excircles. Prove that:
				\(\dfrac{1}{S_1}=\dfrac{1}{S_a}+\dfrac{1}{S_b}+\dfrac{1}{S_c}\). 
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				HINTS: 
						 
					
					1. See Problems
					
					82,
					
					83,
					
					84.    |