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Geometry Problem 1371: Equilic Quadrilateral, 120
Degrees, Congruence, Midpoint, Diagonal, Equilateral Triangle, Parallel,
Collinearity

In the figure below ABCD is an
equilic quadrilateral.
If AB meet DC in M, equilateral triangles AKC, BJC and BLD are drawn
away from AD, and E and G are the midpoint of the diagonals AC
and BD, prove that K, M, J and L are collinear, J
is the midpoint of KL and EG and KL are parallel lines.


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 by Antonio Gutierrez
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