< PREVIOUS PROBLEM | NEXT PROBLEM >
In a rhombus ABCD (figure below), P and F are on AB extended and G and Q are on AD extended, so that angle APQ = angle AGF = 90 degrees. PQ meets CD and FG at N and E, respectively, FG meets BC at M. Prove that FG + EN = EP + FM.
Home | Search | Geometry | Problems | All Problems | Open Problems | Visual Index | 10 Problems | Problems Art Gallery | Art | 911-920 | Triangles | Rhombus | Congruence | Perpendicular lines | Parallel lines | by Antonio Gutierrez
Add a Solution to the Problem 919