 |
|
|
Problem 860: Triangle, Three Medians, Parallel, Parallelogram, Area,
Congruence. Level: High School, SAT Prep, College geometry
|
|
The figure shows a triangle ABC. with
the medians AMA, BMB, and CMC.
BE is parallel to AC and MBMA extended
cuts BE at D. Prove that (1) AMA = DMC, BMB
= DC; (2) Area of the triangle CDMC is 3/4 the area of
the triangle ABC.
|
|
|
More Geometry Problems:
|
|
 |
|
|
 |
Heron's Formula with medians |
|
 |
Geometry Problem 859
Isosceles Right Triangle, Angles,18, 45 Degrees, Congruence, Perpendicular bisector. |
|
 |
Geometry Problem 858
Isosceles Right Triangle, Cevian, Ratio 2:1, 45 Degrees, Congruence, Angles, Auxiliary Lines. |
|
 |
Geometry Problem 857
Triangle, Median, Midpoint, Angles, 30, 45 Degrees, Congruence, Auxiliary Lines. |
|
|
|
|
|
 |
|