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		The figure below shows a triangle ABC, 
		medians AD, BE, CF, and centroid G. O1, O2, O3, O4 are the circumcenters of 
		triangles AFG, AGE, BGF, and BGD, respectively. O1O2 cuts O4O3 
		at H. CP is parallel to AD (P on BE extended). Prove 
		that HO3.CP = HO1.GP.
 
				 
 
						
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