In the figure, D is the incenter of right triangle ABC, \(e\) and \(f\)
are the inradii of the tangential quadrilaterals AGDH and CMDH, respectively.
Prove that \(BD=2\cdot\sqrt {e\cdot f}\)
Geometry Problems
Open Problems
Visual Index
All Problems
Right Triangle
Triangle
Circle
Circle Tangent Line
Incircle, Incenter
Tangential Quadrilateral
Quadrilateral
Square
Angle Bisector
Triangle Centers
Perpendicular lines
Parallel lines
Metric Relations
Geometric Mean
View or Post a solution