In the figure, D is the incenter of right triangle ABC, \(e\) and \(f\)
are the inradii of the tangential quadrilateral AGDH and CMDH, respectively.
Prove that \(BD=2\cdot\sqrt {e\cdot f}\)

- Inradius (plural inradii) is the radius of an incircle.
- Incircle is a circle inscribed within another shape touching every side of it at one point.
- Incenter is the center point of an incircle.
- Tangential quadrilateral is a convex quadrilateral whose sides all can be tangent to an incircle

Geometry Problems

Open Problems

Visual Index

Ten problems: 1411-1420

All Problems

Right Triangle

Triangle

Circle

Circle Tangent Line

Incircle, Incenter

Tangential Quadrilateral

Quadrilateral

Square

Angle Bisector

Triangle Centers

Perpendicular lines

Parallel lines

Metric Relations

Geometric Mean

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