In the figure below,
ABC is an isosceles triangle (AB = BC) with altitude BE = h. D is a point on
AC, r_{1} is the exradius of the triangle ABD corresponding to AD and r_{2} is the exradius of
the triangle DBC corresponding to BC. Prove that r_{2} - r_{1}
= h.

*BD is called an interior
cevian of triangle ABC. *

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Typography of problem 1375.

Geometry Problems

Ten problems: 1371-1380

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Triangle

Isosceles triangle

Exradius

Cevian

Circle

Altitude

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