Proposition

In the figure below, ABC is an isosceles triangle (AB = BC) with altitude BE = h. D is a point on AC, r₁ is the exradius of the triangle ABD corresponding to AD and r₂ is the exradius of the triangle DBC corresponding to BC. Prove that r₂ - r₁ = h.

BD is called an interior cevian of triangle ABC.
 

See solution below

See also:
Typography of problem 1375.