Geometry Problem 1279

Elements: Parallelogram, Midpoint, Triangle, Area, 3/10.

In a parallelogram ABCD of area S, E is the midpoint of AB and F midpoint of BC. AF cuts DE at G. If S₁ is the area of the triangle FGD, prove that S₁ = (3/10) S.
 

See also:
Geometry Problems
1271-1280
Visual Index
Open Problems
All Problems
Triangles
Parallelogram
Midpoint
Parallelogram Area
Triangle Area

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