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                ABC is an equilateral triangle and D is a point on BC. AE is the bisector of angle DAC (E on BC). 
				The circumcircle of triangle ABD cuts AE at F and DF extended 
				meets AC at G. Prove that (1) BF = AF; (2) FE = FG.This entry contributed by Sumith Peiris, Moratuwa, Sri Lanka.
 
 
		 
 
 
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