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The figure shows a right triangle ABC and the external squares ABDE and BCFG. AF meets BC at M, CE meets AB at N and MN extended meets CA extended at P. Prove that angle P = angle BAC - 45 degree.

Home | Search | Geometry | Problems | All Problems | Open Problems | Visual Index | 1101-1110 | Right Triangle | Square | Triangle & Squares | Angle | 45 degree | Email | Post a comment or solutionLast updated: Apr 10, 2015 by Antonio Gutierrez