Online Geometry Problems

Online Geometry Problem 121: Triangle, Median, Similarity and Area. Level: High School, College, Mathematics Education

In the figure below, given a triangle ABC of area S, the medians BM and CN meet at G. Let be BD = 2 CD, the cevian AD meets BM and CN at E and F respectively. Area of triangle EFG is S1. Prove that: GE/EM = 2/3, GF/CF = 1/3 and
S1 = S/60. View or post a solution.

Elearning 121:Similarity and Area

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