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              In the figure below, given a 
				quadrilateral ABCD, M and N are the midpoints of AC and BD 
				respectively. If S, S1, S2, and S3 
				are the areas of the quadrilaterals ABCD,BCNA, BCDM, and BCNM 
				respectively, prove that: \(S_1 = S_2 = \dfrac{S}{2} = 2\cdot S_3\).
 
                
  
				 
 
						
 
				 
				
				
				HINTS:  
 
				1. AREA OF A TRIANGLE:  
				Median Area Fact: 
				A median divides the triangle into 
				two triangles of equal area. 
                
					  
				
 
  
  
  
 
 
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