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Geometry Problem 1369: Equilic Quadrilateral, Congruence, Midpoint, 60-120 Degrees Rhombus or Polyiamond

Proposition

In the figure below ABCD is an equilic quadrilateral. Prove that the midpoints E, G, F, and H of the diagonals and the sides BC and AD always determine a 60-120 degrees rhombus or polyiamond (diamond).



Geometry Problem 1369 Equilic Quadrilateral, Congruence, Midpoint, 60-120 Degrees Rhombus or Polyiamond, diamond

 

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