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Geometry Problem 451: Triangle, Median, Congruence, Proportional Segments
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The figure shows a triangle ABC with the
median BD and the line FE so that BE = BF. If AB = c, BC = a, FG = x, and GE = y, prove
that .
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More Problems:
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![Triangle, Circle, Tangent](../education/p452_triangle_circle_1.jpg) |
Proposed Problem 452.
Triangle, Circle, Tangent, Proportional Segments. |
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![Triangle, Median, Cevian](../problem/p450_triangle_median_1.jpg) |
Proposed Problem 450.
Triangle, Median, Cevian, Congruence, Proportional Segments. |
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![Circle, Diameter, Sagitta](../problem/p449_circle_sagitta_1.jpg) |
Proposed Problem 449.
Congruent Tangent Circles, Diameter, Sagitta, Arc, Perpendicular, Chord. |
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![Tangent circles, diameter](../problem/p448_tangent_circle_1.jpg) |
Proposed Problem 448.
Tangent Circles, Diameter, Perpendicular, Chord. |
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![Collinear Points Index](../geometry/collinear_points_index.jpg) |
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