Online Geometry Problems

Online Geometry Problem 979: Triangle, Cevian, Angle Bisector, Concurrency, 90 Degrees, Perpendicular. Level: High School, College, Mathematics Education

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The figure below shows a triangle ABC with a cevian BD. DE is the bisector of angle ADB, CE and BD meet at O, AO extended meets BC at F. Prove that (1) DF is the bisector of angle BDC; (2) angle EDF = 90 degrees.

 

Geometry Problem 979: Triangle, Cevian, Angle Bisector, Concurrency, 90 Degrees, Perpendicular
 


 

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