The figure below shows a parallelogram ABCD,
AE is the bisector of angle BAD. If AE and DC meet at F, prove that the
circumcenter Q of triangle CEF lies on the circumcircle of triangle BCD.
Search | Geometry
All Problems |
| Triangles | Angle Bisector
Circumcircle / circumcenter |
Solution / comment | By Antonio Gutierrez