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The figure below shows the squares ABCD and DEFG (E on CD). GE extended meets BC at H. HK is perpendicular to AE (K on DG). Prove that AH and HK are congruent.

See also: Art of problem 1312

Home | Geometry | Problems | All Problems | Open Problems | Visual Index | 1311-1320 | Triangle | Square | Perpendicular line | Angle | Congruence | View or Post a solution | by Antonio Gutierrez