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# Geometry Problem 1298

### Elements: Arbelos, Semicircles, Diameters, Circle, Incircle, Tangent, Angle Bisector,
Perpendicular, Midpoint

The figure below shows an arbelos ABC (AB, BC, and AC are semicircles of centers O_{1}, O_{2}, and O).
The incircle I of the arbelos is tangent to semicircles AC, AB, and BC at T,
T_{1}, and T_{2}, respectively. The bisector of the angle
ATC cuts the incircle at P and IP extended cuts AC at H. Prove that (1) IH
is perpendicular to AC; (2) P is the midpoint of IH.

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### Mosaic of problem 1298 in Motion using Mobile Apps, iPad

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