Online Geometry Problems

Online Geometry Problem 758: Equilateral Triangle, Cevians, Trisection of sides, Congruence, Perpendicular, 90 Degrees. Level: High School, College, Mathematics Education

The figure shows an equilateral triangle ABC with AE = BD = AB/3. If the cevians AD and CE meet at F, prove that BF is perpendicular to CE. This entry contributed by Ajit Athle.
 

Equilateral triangle, Trisection, COngruence, 90 Degrees, Perpendicular
 

Home | SearchGeometry | Problems | All Problems | Open Problems | Visual Index | 751-760 | Triangles | Equilateral Triangle | Congruence | Perpendicular | Segment Trisection | Email | Solution / comment | By Antonio Gutierrez