Problem 393: Triangle, Orthocenter, Circumcircles, Congruence, Collinear

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The figure shows a triangle ABC with the orthocenter D (point where altitudes intersect). Circles 1, 2 (center E), 3 (center F), 4 (center G), and 5 are the circumcircles of triangles ABC, ADB, BDC, ADC, and EFG, respectively. Circle 6 is tangent to circles 2, 3, and 4 at points H, M, and N, respectively. Prove that: (1) Circles 1,2,3,4,5 are congruent. (2) D is the center of circle 5. (3) D is the center of circle 6. (4) Points H,B,M are collinear, H,A,N are collinear, and M,C,N are collinear. (5) Points D,E,H are collinear, D,F,M are collinear, and D,G,N are collinear. Post a comment or solution.
 

Triangle, Orthocenter, Circumcircles
 

See Also:

 

Classical Theorems

 

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Square, Circle

Proposed Problem 394.
Square, 90 Degree Arc, Diagonal, Congruence.

 

Triangle, Parallel, Concurrent lines

Proposed Problem 392.
Triangle, Parallel lines, Concurrent lines.

 

Triangle, Parallel, Collinear points

Proposed Problem 391.
Triangle, Parallel lines, Collinear points.


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