Geometry Problem 166. Parallelogram, Diagonal, Triangles, Areas. Level: High School, Honors Geometry, College, Math Education
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In parallelogram ABCD, point E lies
within triangle BCD, and lines BD and AE intersect at point F.
Prove that the area of triangle ABF is equal to the sum of the
areas of triangles BCE and DEF.
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Area of a Parallelogram | Email
| by Antonio Gutierrez
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