Dynamic Geometry 1473: Kosnita's Theorem, Triangle, Four Circumcenters, Concurrent Line, Step-by-step Illustration

The dynamic geometry figure below shows a triangle ABC with the circumcenter O. If OA, OB, and OC, are the circumcenters of triangles BOC, AOC, and AOB, respectively, prove that lines AOA, BOB, and COC are concurrent.

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Static Diagram of Geometry Problem 1473

Kosnita's Theorem, Triangle, Four Circumcenters, Concurrent Line, Step-by-step Illustration, iPad Apps


Poster of the Kornita's Theorem 1473 using iPad Apps

Dynamic Geometry  1473: Kosnita Theorem, Four Circumcenters, Concurrent Line, Step-by-step Illustration Using GeoGebra, iPad Apps

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Classroom Resource:
Interactive step-by-step animation using GeoGebra

This step-by-step interactive illustration was created with GeoGebra.

  • To explore (show / hide): click/tap a check box.
  • To stop/play the animation: click/tap the icon in the lower left corner.
  • To go to first step: click/tap the "Go to step 1" button.
  • To manipulate the interactive figure: click/tap and drag the blue points or figures.

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Geometry Problem 1473 Solution(s)