In the figure below,
ABC is an isosceles triangle (AB = BC) with altitude BE = h. D is a point on
AC, r_{1} is the exradius of the triangle ABD corresponding to AD and r_{2} is the exradius of
the triangle DBC corresponding to BC. Prove that r_{2} - r_{1}
= h.

*BD is called an interior
cevian of triangle ABC. *

See also:

Typography of problem 1375.