The figure shows a quadrilateral ABCD with
AC = CD and angle ACB = angle ACD = 45 degrees. Points
F and E are on CD so that AE is parallel to BC, AB = BE and BE = 2CF. Prove
that BD = 2BF = 3BC. This entry contributed by Sumith Peiris, Moratuwa, Sri Lanka.
See also:
Art and typography of problem 1324
