Geometry Problem 1282

Elements: Three Squares, Common Vertex, Midpoint, Perpendicular, 90 Degrees.

The figure below shows three squares ABCD, A1B1CD1, and A1B2C2D2. If M is the midpoint of BB2, prove that (1) B1M is perpendicular to DD2; (2) DD2 = 2B1M.
 

Geometry Problem 1282: Three Squares, Common Vertex, Midpoint, Perpendicular, 90 Degrees


See also:
Geometry Problems
1281-1290
Visual Index
Open Problems
All Problems
Triangle
Square
Midpoint
Perpendicular lines


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Geometry Art of Problem 1282: Three Squares, Typography, Mobile Apps, iPad.

 

Geometry Problem 1282: Geometry Art of Problem 1282: Three Squares, Typography, Mobile Apps, iPad