Geometry Problem 1279

Elements: Parallelogram, Midpoint, Triangle, Area, 3/10.

In a parallelogram ABCD of area S, E is the midpoint of AB and F midpoint of BC. AF cuts DE at G. If S1 is the area of the triangle FGD, prove that S1 = (3/10) S.
 

Geometry Problem 1279: Parallelogram, Midpoint, Triangle, Area, 3/10


See also:
Geometry Problems
Visual Index
Open Problems
All Problems
Triangles
Parallelogram
Midpoint
Parallelogram Area
Triangle Area


View or Post a solution