In a
parallelogram ABCD of area S, E is the midpoint of AB and F midpoint of BC. AF cuts DE at
G. If S1 is the area of the triangle FGD, prove that S1 =
(3/10) S.
See also:
Geometry Problems
1271-1280
Visual Index
Open Problems
All Problems
Triangles
Parallelogram
Midpoint
Parallelogram Area
Triangle Area