# Geometry Problem 1279

### Elements: Parallelogram, Midpoint, Triangle, Area, 3/10.

In a
parallelogram ABCD of area S, E is the midpoint of AB and F midpoint of BC. AF cuts DE at
G. If S_{1} is the area of the triangle FGD, prove that S_{1} =
(3/10) S.

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1271-1280

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Parallelogram Area

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