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Online Math: Geometry Problem 1225: Equilateral Triangle, Circumcircle, Angle Bisector, Congruence. Tiled background image: Intihuatana, Machu Picchu. Level: College, High School.

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ABC is an equilateral triangle and D is a point on BC. AE is the bisector of angle DAC (E on BC). The circumcircle of triangle ABD cuts AE at F and DF extended meets AC at G. Prove that (1) BF = AF; (2) FE = FG.
This entry contributed by Sumith Peiris, Moratuwa, Sri Lanka. 
 

Geometry Problem 1225: Equilateral Triangle, Circumcircle, Angle Bisector, Congruence.
 
 

 

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Last updated: Jun 6, 2016