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The figure shows a triangle ABC with incenter I, circumcircle O, excenter E corresponding to AC and circumradius R. ED is perpendicular to AC so that D is on IO extended. Prove that DE = 2R

See also: Triangles Circle Incenter Circumcircle Excenter Angle Bisector Congruence

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Post or view a solution to the problem 1207 Last updated: Apr 14, 2016