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Geometry Problem 1116: Right Triangle, Angle Trisection, 90 Degrees, Perpendicular Lines. Level: High School, SAT Prep, Honors Geometry, College, Math Education

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The figure below shows a right triangle ABC with AA1 and AA2 trisectors of angle BAC, similarly CC1 and CC2 trisectors of angle ACB. AA1 meets CC2 and CC1 at C3 and B1, respectively. AA2 meets CC2 and CC1 at B2 and A3, respectively. If B1B2 meets AC at B3, prove that angle A3B3C3 = 90 degrees. 

Infographic Geometry problem 1116: Right Triangle, Angle Trisection, 90 Degrees, Perpendicular Lines
 

 

 

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Last updated: Apr 30, 2015 by Antonio Gutierrez.