Geometry Problems, Online Education

Math: Geometry Problem 1109: Right Triangle, External Squares, Catheti, Cathetus, 45 Degree, Angle. Level: High School, College

< PREVIOUS PROBLEM  |  NEXT PROBLEM >

The figure shows a right triangle ABC and the external squares ABDE and BCFG. AF meets BC at M, CE meets AB at N and MN extended meets CA extended at P. Prove that angle P = angle BAC - 45 degree.
 
 
 

Geometry Problem 1109 Right Triangle, External Squares, Catheti, Cathetus, 45 Degree, Angle
 
 
 
 

Selected Topics

Home | SearchGeometry | Problems | All Problems | Open Problems | Visual Index | 1101-1110 | Right TriangleSquare | Triangle & Squares | Angle | 45 degree | Email | Post a comment or solution
Last updated: Apr 10, 2015 by Antonio Gutierrez