Problem 207.
Right Triangle, Hypotenuse, Inradius, Exradius relative to
the hypotenuse
In the figure below, BAC is
a right triangle of hypotenuse BC = a. If r is the inradius, ra is
the exradius relative to the hypotenuse, and the points D, E, F,
and G are the points of tangency, prove that: a = DG = EF
= ra - r.
Post
a
comment.
