In the figure below, BAC is a right
triangle with the incircle and the three excircles. If s is the
semiperimeter, points D, E, F, G, H, J, K, L, M, and N are the
points of tangency, and rb and rc are de
exradii relative to the catheti (legs), prove that:
rb = s - c = AD = AE = BF = BH = CJ = CL, similarly rc
= s - b = AM = AG = CH = CN = BK = BL.
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