Problem 649: Archimedes' Book of Lemmas: Proposition 10, Tangent, Chord, Parallel

Online Geometry

AB and AC are two tangents to a circle and AD cuts it. Let CE be the chord through C parallel to AD, and let BE meet AD in F. Then, if FG be drawn perpendicular to CE, it will bisect it in G. See also iPad Productivity Apps; Adobe Spark Post

  


 
 

Home | SearchGeometry | Problems | All Problems | Visual Index | 641-650 | Archimedes' Lemmas | Circles | Perpendicular | Angles | Midpoints | Chord | Perpendicular Chords | Parallel Chords | Email | Solution / comment | by Antonio Gutierrez